I’m trying to write a simple Fibonacci app in Fortran, and it’s my first time with the language. I’m having an issue where I have a function which receives and returns an integer, yet the compiler says: Error: Return type mismatch of function ‘fibonacci’ at (1) (REAL(4)/INTEGER(4)).
integer :: user_num
integer :: fib_result
print *, 'Enter a number: '
fib_result = fibonacci(user_num)
print *, 'fibonacci(', user_num , ') = ', fib_result
recursive function fibonacci(a) result(b)
integer, intent(in) :: a
integer :: b
if (a <= 1) then
b = 1
b = fibonacci(a-1) + fibonacci(a-2)
end function fibonacci
What am I doing wrong with the function and/or data type?
From ISO/IEC 1539 : 1991 (E) and later
"The CONTAINS statement separates the body of a main program, module, or subprogram from any internal or module subprograms it may contain. The CONTAINS statement is not executable. "
The simplest, though not as elegant as hints above, is adding fibonacci to any of integer declarations in main program. Or, just a bit more elegant, a separate declaration integer, external :: fibonacci
No, in Fortran this declares an identifier to be a name of a procedure (subroutine or function). Mostly used to be able to send a procedure as an argument to another procedure. Required in old Fortran.
Now in Modern Fortran (90+) obviously not needed if one creates explicit interface of such a procedure (by use of interface block or by storing the procedure in a module or after contains statement, as an internal one)
@rjzak , if you’re interested further in Fortran, please see this thread.
Not too long ago, a respondent on this thread of yours had asked about sample code to illustrate briefly the features of Fortran to those looking at Fortran for the first time. I had chosen a Fibonacci function example for it as you will see in the code in that thread! Hopefully you will find the code sample of some interest. You may know of free Intel oneAPI Fortran compiler you can try toward the example.
Thank you. Fortran has always been in the back of my mind for historical reasons. I’ve been a programmer for a long time, in C/C++, Go, Java, Python, Rust. Never learned Fortran. I’m here because I found the recent paper on arxiv about the state of Fortran, so I wanted to investigate.
Yes, a procedure name, used as an actual argument, works as a ‘self-pointer’, very similar to how a function name is treated in C. As it has no parentheses in this context, it must be previously declared to be a subprogram, not an ordinary scalar variable.
Not to be confused with procedure pointers (Fortran 2003+) which can also be used for that purpose.
The difference between true procedure pointers in Fortran i C is, AFAIU, that a function identifier in C is equivalent to a pointer to that function. Not so in Fortran.