GCC 16.1 was officially released today:
2 Likes
does anyone have a ./configure line that has worked? I am not being able to compile gcc
1 Like
Jerry guided me to compile GCC a few weeks ago.
I had created a gcc-dev directory with three subdirs:
trunk/(gcc sources)objdir/(empty)usr/(empty)
First, in trunk/:
$ ./contrib/download_prerequisites
$ sudo dnf install gcc-c++ glibc-devel.i686
From objdir/, I had in my script:
readonly repertoire=/home/my_login/gcc_dev
../trunk/configure --prefix="${repertoire}"/usr --enable-languages=c,c++,fortran --enable-multilib --enable-libgomp --disable-bootstrap
make -j10 1>/dev/null && make install 1>/dev/null
Drink you coffee… 
Finally I tested my snippets with:
gcc_dev/my_snippets$ LD_LIBRARY_PATH=/home/my_login/gcc_dev/usr/lib:/home/my_login/gcc_dev/usr/lib64
gcc_dev/my_snippets$ export LD_LIBRARY_PATH
gcc_dev/my_snippets$ ../usr/bin/gfortran -fcoarray=lib collective.f90 -lcaf_shmem
I should update the Fortran Wiki page with those info.
1 Like
For adventurers only, GFortran 16.1 has arrived in Fedora Rawhide (development distribution):
Next steps should be Fedora 44 Testing, then Stable.
It has just arrived in Fedora Linux 44:
$ gfortran --version
GNU Fortran (GCC) 16.1.1 20260501 (Red Hat 16.1.1-1)
Copyright © 2026 Free Software Foundation, Inc.
1 Like
Does gfortran 16 have an entirely new front-end? What kinds of problems should we watch for with new front end code?
The gfortran front end is an evolution of what has existed for many years. So you shouldn’t have to change anything. (Modulo bug fixes. One I know about is that Jerry D and I worked to get certain INQUIRE return values corrected.) The new front ends over the past couple of major releases are Algol 68 and COBOL.
2 Likes
DO CONCURRENT can speedup like openMP in gfortran 16.1?
I’ve had little success with GNU accelerating do concurrent, if you have good experiences please do tell
2 Likes
the solution was to do an out of source build…
1 Like
Indeed @jorgeg , that’s an advice that Jerry gave me, after my first attempts.
1 Like
Jerry is smart! thanks so much
2 Likes
That is definitely a prerequisite to be a GFortran developer 
. I guess he compiles GCC every day, so you can trust him.
1 Like
Another news about GCC (17 ?):
I don’t know if Fortran will be concerned, but if it is a back-end… LFortran has already a WebAssembly back-end.
1 Like
I did some comparative bench marking of gfortran and Intel ifx.
Here is the source code of the main program.
! include ‘precision_module.f90’
! include ‘integer_kind_module.f90’
! Included in the timing_module
include ‘timing_module.f90’
program ch3403
use precision_module
use timing_module
implicit none
real (dp) :: fortran_internal_pi
real (dp) :: partial_pi
real (dp) :: coarray_pi
real (dp) :: width
real (dp) :: total_sum
real (dp) :: x
real (dp), codimension [ * ] :: partial_sum
integer :: n_intervals
integer :: i
integer :: j
integer :: current_image
integer :: n_images
fortran_internal_pi = 4.0_dp*atan(1.0_dp)
n_images = num_images()
current_image = this_image()
if (current_image==1) then
print *, ’ Number of images = ', n_images
call start_timing()
end if
n_intervals = 100000
do j = 1, 5
width = 1.0_dp/real(n_intervals, dp)
total_sum = 0.0_dp
partial_sum = 0.0_dp
do i = current_image, n_intervals, n_images
x = (real(i,dp)-0.5_dp)width
partial_sum = partial_sum + f(x)
end do
partial_sum = partial_sumwidth
sync all
if (current_image==1) then
do i = 1, n_images
total_sum = total_sum + partial_sum[ i ]
end do
coarray_pi = total_sum
print 100, n_intervals, time_difference()
print 110, coarray_pi, abs(coarray_pi-fortran_internal_pi)
end if
n_intervals = n_intervals*10
sync all
end do
if (current_image==1) then
call end_timing()
end if
100 format (’ n intervals = ‘, i12, ’ time =’, f18.6)
110 format (’ pi = ', f20.16, /, ’ difference = ', f20.16)
contains
real (dp) function f(x)
implicit none
real (dp), intent (in) :: x
f = 4.0_dp/(1.0_dp+x*x)
end function
end program
Here are the timing details.
| Intervals | Average of 10 runs | ||
|---|---|---|---|
| gfortran | 100,000 | 0.000408 | |
| gfortran | 1,000,000 | 0.000907 | |
| gfortran | 10,000,000 | 0.001538 | |
| gfortran | 100,000,000 | 0.009646 | |
| gfortran | 1,000,000,000 | 0.098619 | |
| gfortran | Total | 0.111455 | |
| Intel ifx | 100,000 | 0.000275 | |
| Intel ifx | 1,000,000 | 0.000289 | |
| Intel ifx | 10,000,000 | 0.001027 | |
| Intel ifx | 100,000,000 | 0.007884 | |
| Intel ifx | 1,000,000,000 | 0.108436 | |
| Intel ifx | Total | 0.118361 | |
| gfortran | 16.1.1 20260501 | ||
| ifx | 2026.0.0 | ||
| Fedora | Fedora Linux 44 | Workstation edition | |
| Redhat | 16.1.1-1 | ||
| Processor | Intel I9 | 10980XE | |
| hyper-v | |||
| memory | 32 GB | ||
| cores | 16 |
The source files are on our web sites.
There is a tar file of all the source files.
1 Like